integral of (x^2-2x+5)

Lösung

\int (x^{2} - 2 x + 5) d x

\frac{x ^{3}}{3} - x^{2} + 5 x + C

Schritte zur Lösung

\int x^{2} - 2 x + 5 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} d x - \int 2 x d x + \int 5 d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int 2 x d x = x^{2}

\int 5 d x = 5 x

= \frac{x ^{3}}{3} - x^{2} + 5 x

Füge eine Konstante zur Lösung hinzu

= \frac{x ^{3}}{3} - x^{2} + 5 x + C

\int_{- 8}^{8} (e^{x} - e^{- x})^{2} d x

\int_{0}^{2} x + 1 d x

\int_{0}^{4} x - 2 x d x

\int - x x - 1 d x

\frac{\partial}{\partial x} (x ln (x^{2} + y^{2}))