integral from 0 to 4 of x-2sqrt(x)

Lösung

\int_{0}^{4} x - 2 x d x

- \frac{8}{3}

Dezimale

- 2.66666 \dots

Schritte zur Lösung

\int_{0}^{4} x - 2 x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} x d x - \int_{0}^{4} 2 x d x

\int_{0}^{4} x d x = 8

\int_{0}^{4} 2 x d x = \frac{32}{3}

= 8 - \frac{32}{3}

Vereinfache

8 - \frac{32}{3} : - \frac{8}{3}

= - \frac{8}{3}

\int - x x - 1 d x

\frac{\partial}{\partial x} (x ln (x^{2} + y^{2}))

\frac{\partial}{\partial x} (4 x (5 + y)^{- 1})

t an g e n t f (x) = x^{3} + 2 x, at x = 0

\frac{\partial}{\partial x} (\frac{- cos ( x )}{x})