What is the tangent of f(x)= 7/(x^2)-6x^2,\at x=5 ?

The tangent of f(x)= 7/(x^2)-6x^2,\at x=5 is y=-7514/125 x+3771/25

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tangent of f(x)= 7/(x^2)-6x^2,\at x=5

tangent

y = - \frac{7514}{125} x + \frac{3771}{25}

Solution steps

Find the tangent point:

(5, - \frac{3743}{25})

Find the slope of

f (x) = \frac{7}{x ^{2}} - 6 x^{2} : \frac{df ( x )}{d x} = - \frac{14}{x ^{3}} - 12 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{7514}{125}

Find the line with slope m=

- \frac{7514}{125}

and passing through

(5, - \frac{3743}{25}) : y = - \frac{7514}{125} x + \frac{3771}{25}

y = - \frac{7514}{125} x + \frac{3771}{25}

What is the tangent of f(x)= 7/(x^2)-6x^2,\at x=5 ?
The tangent of f(x)= 7/(x^2)-6x^2,\at x=5 is y=-7514/125 x+3771/25