What is the integral from 1 to 3 of 4r^4ln(r) ?

The integral from 1 to 3 of 4r^4ln(r) is 4(-242/25+243/5 ln(3))

integral from 1 to 3 of 4r^4ln(r)

\int_{1}^{3} 4 r^{4} ln (r) d r

4 (- \frac{242}{25} + \frac{243}{5} ln (3))

Decimal

174.85022 \dots

Solution steps

\int_{1}^{3} 4 r^{4} ln (r) d r

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int_{1}^{3} r^{4} ln (r) d r

Apply Integration By Parts

= 4 [\frac{1}{5} r^{5} ln (r) - \int \frac{r ^{4}}{5} d r]_{1}^{3}

\int \frac{r ^{4}}{5} d r = \frac{r ^{5}}{25}

= 4 [\frac{1}{5} r^{5} ln (r) - \frac{r ^{5}}{25}]_{1}^{3}

Compute the boundaries:

- \frac{242}{25} + \frac{243}{5} ln (3)

= 4 (- \frac{242}{25} + \frac{243}{5} ln (3))

d er i v a t i v e 2^{x^{2} + x}

\int ∣ x - 2 ∣ d x

t an g e n t x^{4} + 7 e^{x}

n = 0 \sum \infty 9 (\frac{5}{12})^{n}

\frac{d}{d x} ((x^{2} + 1)^{\frac{1}{2}})

What is the integral from 1 to 3 of 4r^4ln(r) ?
The integral from 1 to 3 of 4r^4ln(r) is 4(-242/25+243/5 ln(3))