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受欢迎的微积分 >

tangent x^4+7e^x

解答

切线

x^{4} + 7 e^{x}

解答

y = (4 a_{0}^{3} + 7 e^{a_{0}}) x - 3 a_{0}^{4} - 7 a_{0} e^{a_{0}} + 7 e^{a_{0}}

求解步骤

计算在一般点

x = a_{0}

的切线

找到切点:

(a_{0}, a_{0}^{4} + 7 e^{a_{0}})

计算

y = x^{4} + 7 e^{x}

的斜率:

\frac{d y}{d x} = 4 x^{3} + 7 e^{x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 4 a_{0}^{3} + 7 e^{a_{0}}

找到斜率 m=

4 a_{0}^{3} + 7 e^{a_{0}}

且穿过

(a_{0}, a_{0}^{4} + 7 e^{a_{0}})

的直线:

y = (4 a_{0}^{3} + 7 e^{a_{0}}) x - 3 a_{0}^{4} - 7 a_{0} e^{a_{0}} + 7 e^{a_{0}}

y = (4 a_{0}^{3} + 7 e^{a_{0}}) x - 3 a_{0}^{4} - 7 a_{0} e^{a_{0}} + 7 e^{a_{0}}

作图

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