What is the solution for y^'=y(xy^5+3) ?

The solution for y^'=y(xy^5+3) is y=\sqrt[5]{(45e^{15x})/(-15xe^{15x)+e^{15x}+c_{1}}}

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y^'=y(xy^5+3)

y^{^{'}} = y (x y^{5} + 3)

y = 5 \frac{45 e ^{15 x}}{- 15 x e ^{15 x} + e ^{15 x} + c _{1}}

Solution steps

y^{'} (x) = y (x y^{5} + 3)

Solve Bernoulli ODE:

y = 5 \frac{45 e ^{15 x}}{- 15 x e ^{15 x} + e ^{15 x} + c _{1}}

y = 5 \frac{45 e ^{15 x}}{- 15 x e ^{15 x} + e ^{15 x} + c _{1}}

x \to - 3 lim (x^{3} - 2 x^{2} + x + 7)

y^{^{'}} - y = 2 t e^{2 t}, y (0) = 1

\frac{\partial}{\partial x} (sin (x yz))

in v erse l a pl a ce \frac{1}{s ( s ^{2} + 25 )}

t an g e n t y = 4 tan (x), at x = \frac{π}{3}

What is the solution for y^'=y(xy^5+3) ?
The solution for y^'=y(xy^5+3) is y=\sqrt[5]{(45e^{15x})/(-15xe^{15x)+e^{15x}+c_{1}}}