What is (\partial)/(\partial x)(sin(xyz)) ?

The answer to (\partial)/(\partial x)(sin(xyz)) is cos(xyz)yz

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(\partial)/(\partial x)(sin(xyz))

\frac{\partial}{\partial x} (sin (x yz))

cos (x yz) yz

Solution steps

\frac{\partial}{\partial x} (sin (x yz))

Treat

y, z

as constants

Apply the chain rule:

cos (x yz) \frac{\partial}{\partial x} (x yz)

= cos (x yz) \frac{\partial}{\partial x} (x yz)

\frac{\partial}{\partial x} (x yz) = yz

= cos (x yz) yz

in v erse l a pl a ce \frac{1}{s ( s ^{2} + 25 )}

t an g e n t y = 4 tan (x), at x = \frac{π}{3}

\int \frac{3 y}{y ^{2} + z ^{2}} d y

d er i v a t i v e (x - 1)^{12}

81 y^{^{''}} - 18 y^{^{'}} + y = 0

What is (\partial)/(\partial x)(sin(xyz)) ?
The answer to (\partial)/(\partial x)(sin(xyz)) is cos(xyz)yz