What is the integral from 0 to 1 of e^t ?

The integral from 0 to 1 of e^t is e-1

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integral from 0 to 1 of e^t

\int_{0}^{1} e^{t} d t

e - 1

Decimal

1.71828 \dots

Solution steps

\int_{0}^{1} e^{t} d t

Use the common integral:

\int e^{t} d t = e^{t}

= [e^{t}]_{0}^{1}

Compute the boundaries:

e - 1

= e - 1

\int p (p + 8)^{5} d p

\int e^{(2 x)} d x

e x p an d (x^{5} + 2 x) \cdot (x^{3} + x^{2} + x + 7)

\int e^{- x} \cdot cos (w x) d x

y^{^{''}} + y^{^{'}} + y = 0, y (0) = 1, y^{^{'}} (0) = - 1

What is the integral from 0 to 1 of e^t ?
The integral from 0 to 1 of e^t is e-1