What is the integral of e^{tan(v)}sec^2(v) ?

The integral of e^{tan(v)}sec^2(v) is e^{tan(v)}+C

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integral of e^{tan(v)}sec^2(v)

\int e^{t a n (v)} sec^{2} (v) d v

e^{t a n (v)} + C

Solution steps

\int e^{t a n (v)} sec^{2} (v) d v

Apply u-substitution

= \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= e^{u}

Substitute back

u = tan (v)

= e^{t a n (v)}

Add a constant to the solution

= e^{t a n (v)} + C

\int \frac{x e ^{x^{2}}}{e ^{x^{2}} + 2} d x

n = 1 \sum \infty n e^{9 n}

\int sec^{4} (x) \cdot tan^{2} (x) d x

\int_{1}^{8} 9 \frac{ln ( x )}{x ^{2}} d x

t a y l or x^{x^{2}}, 1

What is the integral of e^{tan(v)}sec^2(v) ?
The integral of e^{tan(v)}sec^2(v) is e^{tan(v)}+C