What is the derivative of (3x+1^4) ?

The derivative of (3x+1^4) is 12(3x+1)^3

What is the first derivative of (3x+1^4) ?

The first derivative of (3x+1^4) is 12(3x+1)^3

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\frac{d}{d x} ((3 x + 1)^{4})

12 (3 x + 1)^{3}

Solution steps

\frac{d}{d x} ((3 x + 1)^{4})

Apply the chain rule:

4 (3 x + 1)^{3} \frac{d}{d x} (3 x + 1)

= 4 (3 x + 1)^{3} \frac{d}{d x} (3 x + 1)

\frac{d}{d x} (3 x + 1) = 3

= 4 (3 x + 1)^{3} \cdot 3

Simplify

= 12 (3 x + 1)^{3}

d er i v a t i v e \frac{1}{3 x}

\frac{d}{d x} (\frac{x - 3}{x + 3})

\int_{0}^{1} \frac{37}{4 y - 1} d y

\int_{0}^{3} arctan (x) d x

\frac{\partial}{\partial x} (- sin (x) - sin (2 y))

What is the derivative of (3x+1^4) ?
The derivative of (3x+1^4) is 12(3x+1)^3
What is the first derivative of (3x+1^4) ?
The first derivative of (3x+1^4) is 12(3x+1)^3