What is the derivative of 1/(3x) ?

The derivative of 1/(3x) is -1/(3x^2)

What is the first derivative of 1/(3x) ?

The first derivative of 1/(3x) is -1/(3x^2)

derivative of

\frac{1}{3 x}

- \frac{1}{3 x ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{3 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{3} \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{1}{3} \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{3} (- 1 \cdot x^{- 1 - 1})

Simplify

\frac{1}{3} (- 1 \cdot x^{- 1 - 1}) : - \frac{1}{3 x ^{2}}

= - \frac{1}{3 x ^{2}}

\frac{d}{d x} (\frac{x - 3}{x + 3})

\int_{0}^{1} \frac{37}{4 y - 1} d y

\int_{0}^{3} arctan (x) d x

\frac{\partial}{\partial x} (- sin (x) - sin (2 y))

d er i v a t i v e f (x) = \frac{x ^{2}}{7 + x}

What is the derivative of 1/(3x) ?
The derivative of 1/(3x) is -1/(3x^2)
What is the first derivative of 1/(3x) ?
The first derivative of 1/(3x) is -1/(3x^2)