What is the solution for (df)/(dx)+2f=fx^3 ?

The solution for (df)/(dx)+2f=fx^3 is f(x)=e^{(x^4)/4-2x+c_{1}}

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(df)/(dx)+2f=fx^3

\frac{df}{d x} + 2 f = f x^{3}

f (x) = e^{\frac{x ^{4}}{4} - 2 x + c_{1}}

Solution steps

\frac{df}{d x} + 2 f = f x^{3}

Solve separable ODE:

f (x) = e^{\frac{x ^{4}}{4} - 2 x + c_{1}}

f (x) = e^{\frac{x ^{4}}{4} - 2 x + c_{1}}

n = 0 \sum \infty (\frac{1}{3})^{n}

a re a 2 x^{2} + 3, x, (- 1, 2)

\int_{- 2}^{2} π (4 - x^{2}) d x

(y + 4) \cdot y^{^{'}} = 2 x y + 4 y, y (2) = 1

x \to + 9 - lim (\frac{- 7}{( x + 9 )})

What is the solution for (df)/(dx)+2f=fx^3 ?
The solution for (df)/(dx)+2f=fx^3 is f(x)=e^{(x^4)/4-2x+c_{1}}