What is the integral from-2 to 2 of pi(4-x^2) ?

The integral from-2 to 2 of pi(4-x^2) is pi 32/3

integral from-2 to 2 of pi(4-x^2)

\int_{- 2}^{2} π (4 - x^{2}) d x

π \frac{32}{3}

Decimal

33.51032 \dots

Solution steps

\int_{- 2}^{2} π (4 - x^{2}) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= π \cdot \int_{- 2}^{2} 4 - x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= π (\int_{- 2}^{2} 4 d x - \int_{- 2}^{2} x^{2} d x)

\int_{- 2}^{2} 4 d x = 16

\int_{- 2}^{2} x^{2} d x = \frac{16}{3}

= π (16 - \frac{16}{3})

Join

16 - \frac{16}{3} : \frac{32}{3}

= π \frac{32}{3}

(y + 4) \cdot y^{^{'}} = 2 x y + 4 y, y (2) = 1

x \to + 9 - lim (\frac{- 7}{( x + 9 )})

\int sin^{3} (t) cos (t) d t

d er i v a t i v e \frac{1}{3} (y^{2} + 2)^{\frac{3}{2}}

\frac{d}{d x} (ln (2 ln (x)))

What is the integral from-2 to 2 of pi(4-x^2) ?
The integral from-2 to 2 of pi(4-x^2) is pi 32/3