y^{''}-2/x y^'-(10)/(x^2)=0

Lösung

y^{^{''}} - \frac{2}{x} y^{^{'}} - \frac{10}{x ^{2}} = 0

y = c_{1} x^{3} + c_{2} - \frac{10}{9} - \frac{10}{3} ln (x)

Schritte zur Lösung

y^{''} (x) - \frac{2}{x} y^{'} (x) - \frac{10}{x ^{2}} = 0

Solve linear ODE:

y = c_{1} x^{3} + c_{2} - \frac{10}{9} - \frac{10}{3} ln (x)

y = c_{1} x^{3} + c_{2} - \frac{10}{9} - \frac{10}{3} ln (x)

\int \frac{26}{( x - 1 ) ( x ^{2} + 25 )} d x

\int \frac{2 x - 3}{4 x - x ^{2}} d x

\int_{e}^{e^{2}} \frac{1}{x ln ( x )} d x

\frac{d}{d x} (\frac{40}{1 + 79 e ^{- x}})

\frac{d}{d x} (\frac{x}{x - 7})