What is the derivative of 3x^{-3} ?

The derivative of 3x^{-3} is -9/(x^4)

What is the first derivative of 3x^{-3} ?

The first derivative of 3x^{-3} is -9/(x^4)

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\frac{d}{d x} (3 x^{- 3})

- \frac{9}{x ^{4}}

Solution steps

\frac{d}{d x} (3 x^{- 3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 (- 3 x^{- 3 - 1})

Simplify

3 (- 3 x^{- 3 - 1}) : - \frac{9}{x ^{4}}

= - \frac{9}{x ^{4}}

d er i v a t i v e f (x) = \frac{4 x + 3}{4 x - 3}

s l o p e in t erce pt (- 2, 7), (0, 5)

\frac{d}{d v} (\frac{u}{v})

\frac{\partial}{\partial y} (- x e^{- 3 x y})

\int x e^{m x} d x

What is the derivative of 3x^{-3} ?
The derivative of 3x^{-3} is -9/(x^4)
What is the first derivative of 3x^{-3} ?
The first derivative of 3x^{-3} is -9/(x^4)