derivative of 3x^2+1/(x^3)

Lösung

\frac{d}{d x} (3 x^{2} + \frac{1}{x ^{3}})

6 x - \frac{3}{x ^{4}}

Schritte zur Lösung

\frac{d}{d x} (3 x^{2} + \frac{1}{x ^{3}})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (\frac{1}{x ^{3}})

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (\frac{1}{x ^{3}}) = - \frac{3}{x ^{4}}

= 6 x - \frac{3}{x ^{4}}

x \to 0 - lim (sin (\frac{1}{x}))

\frac{d}{d x} (4 sin (x) - 5 cos (x) + x)

\frac{d}{d x} (\frac{1}{16 x ^{4}})

\frac{\partial}{\partial x} (e^{2 x + 5 y})

\frac{d}{d x} (cos (x - \frac{π}{4}))