What is the integral from-2 to 2 of (32-8y^2) ?

The integral from-2 to 2 of (32-8y^2) is 256/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from-2 to 2 of (32-8y^2)

\int_{- 2}^{2} (32 - 8 y^{2}) d y

\frac{256}{3}

Decimal

85.33333 \dots

Solution steps

\int_{- 2}^{2} 32 - 8 y^{2} d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{2} 32 d y - \int_{- 2}^{2} 8 y^{2} d y

\int_{- 2}^{2} 32 d y = 128

\int_{- 2}^{2} 8 y^{2} d y = \frac{128}{3}

= 128 - \frac{128}{3}

Simplify

128 - \frac{128}{3} : \frac{256}{3}

= \frac{256}{3}

\frac{d}{d x} ((\frac{3 x - 4}{5 x + 2})^{- 5})

d er i v a t i v e f (x) = 5 x^{2} cos (x) + 4 x

d er i v a t i v e 3 x + sin (5 x)

f (x) = ln (cos (x))

\frac{\partial}{\partial x} (\frac{7 y - 7 x}{y ^{2} + 2 x ^{2}})

What is the integral from-2 to 2 of (32-8y^2) ?
The integral from-2 to 2 of (32-8y^2) is 256/3