What is the derivative of 3x+sin(5x) ?

The derivative of 3x+sin(5x) is 3+cos(5x)*5

What is the first derivative of 3x+sin(5x) ?

The first derivative of 3x+sin(5x) is 3+cos(5x)*5

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derivative of

3 x + sin (5 x)

3 + cos (5 x) \cdot 5

Solution steps

\frac{d}{d x} (3 x + sin (5 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) + \frac{d}{d x} (sin (5 x))

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (sin (5 x)) = cos (5 x) \cdot 5

= 3 + cos (5 x) \cdot 5

f (x) = ln (cos (x))

\frac{\partial}{\partial x} (\frac{7 y - 7 x}{y ^{2} + 2 x ^{2}})

(x^{2} - 2 x - 2 sin (x - 2))^{^{'}}

n = 1 \sum \infty \frac{n !}{n !}

\int x cos (n x π) d x

What is the derivative of 3x+sin(5x) ?
The derivative of 3x+sin(5x) is 3+cos(5x)*5
What is the first derivative of 3x+sin(5x) ?
The first derivative of 3x+sin(5x) is 3+cos(5x)*5