What is integral from 0 to 8 of f(x) ?

The answer to integral from 0 to 8 of f(x) is f*32

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integral from 0 to 8 of f(x)

\int_{0}^{8} f (x) d x

f \cdot 32

Solution steps

\int_{0}^{8} f x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= f \cdot \int_{0}^{8} x d x

Apply the Power Rule

= f [\frac{x ^{2}}{2}]_{0}^{8}

Compute the boundaries:

32

= f \cdot 32

\frac{d ^{2}}{d x ^{2}} (x^{\frac{1}{2}})

\frac{\partial}{\partial s} (arctan (rs))

d er i v a t i v e e^{x^{x}}

\int \frac{5 x ^{2}}{( 3 + x ^{3} ) ^{2}} d x

\frac{\partial}{\partial y} (\frac{( x - y )}{( x + y )})

What is integral from 0 to 8 of f(x) ?
The answer to integral from 0 to 8 of f(x) is f*32