What is the d/(d{x)}(sin(3{x}+{y}{z})) ?

The d/(d{x)}(sin(3{x}+{y}{z})) is cos(3{x}+{y}{z})*3

What is the first d/(d{x)}(sin(3{x}+{y}{z})) ?

The first d/(d{x)}(sin(3{x}+{y}{z})) is cos(3{x}+{y}{z})*3

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\frac{d}{d x} (sin (3 x + y z))

cos (3 x + y z) \cdot 3

Solution steps

\frac{d}{d x} (sin (3 x + y z))

Apply the chain rule:

cos (3 x + y z) \frac{d}{d x} (3 x + y z)

= cos (3 x + y z) \frac{d}{d x} (3 x + y z)

\frac{d}{d x} (3 x + y z) = 3

= cos (3 x + y z) \cdot 3

\frac{d}{d x} (x^{0.7})

\int_{0}^{2 π} t^{2} sin (2) d t

\frac{\partial}{\partial v} (sin (u) sin (v))

x \to - 2 lim (2 x^{2} + 5 x + 3)

y = \frac{3 x ^{5} - 7 x ^{2} - 4}{x ^{2}}

What is the d/(d{x)}(sin(3{x}+{y}{z})) ?
The d/(d{x)}(sin(3{x}+{y}{z})) is cos(3{x}+{y}{z})*3
What is the first d/(d{x)}(sin(3{x}+{y}{z})) ?
The first d/(d{x)}(sin(3{x}+{y}{z})) is cos(3{x}+{y}{z})*3