What is the sum from n=0 to infinity of (1/7)^n ?

The sum from n=0 to infinity of (1/7)^n is 7/6

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sum from n=0 to infinity of (1/7)^n

n = 0 \sum \infty (\frac{1}{7})^{n}

\frac{7}{6}

Decimal

1.16666 \dots

Solution steps

n = 0 \sum \infty (\frac{1}{7})^{n}

Apply Series Geometric Test:

\frac{7}{6}

= \frac{7}{6}

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What is the sum from n=0 to infinity of (1/7)^n ?
The sum from n=0 to infinity of (1/7)^n is 7/6