What is the integral of 4t^4e^{6t^5} ?

The integral of 4t^4e^{6t^5} is 2/15 e^{6t^5}+C

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integral of 4t^4e^{6t^5}

\int 4 t^{4} e^{6 t^{5}} d t

\frac{2}{15} e^{6 t^{5}} + C

Solution steps

\int 4 t^{4} e^{6 t^{5}} d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int t^{4} e^{6 t^{5}} d t

Apply u-substitution

= 4 \cdot \int \frac{e ^{6 u^{\frac{5}{4}}} u ^{\frac{1}{4}}}{4} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \frac{1}{4} \cdot \int e^{6 u^{\frac{5}{4}}} u^{\frac{1}{4}} d u

Apply u-substitution

= 4 \cdot \frac{1}{4} \cdot \int \frac{4 e ^{6 v}}{5} d v

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \frac{1}{4} \cdot \frac{4}{5} \cdot \int e^{6 v} d v

Apply u-substitution

= 4 \cdot \frac{1}{4} \cdot \frac{4}{5} \cdot \int e^{w} \frac{1}{6} d w

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \frac{1}{4} \cdot \frac{4}{5} \cdot \frac{1}{6} \cdot \int e^{w} d w

Use the common integral:

\int e^{w} d w = e^{w}

= 4 \cdot \frac{1}{4} \cdot \frac{4}{5} \cdot \frac{1}{6} e^{w}

Substitute back

= 4 \cdot \frac{1}{4} \cdot \frac{4}{5} \cdot \frac{1}{6} e^{6 (t^{4})^{\frac{5}{4}}}

Simplify

4 \cdot \frac{1}{4} \cdot \frac{4}{5} \cdot \frac{1}{6} e^{6 (t^{4})^{\frac{5}{4}}} : \frac{2}{15} e^{6 t^{5}}

= \frac{2}{15} e^{6 t^{5}}

Add a constant to the solution

= \frac{2}{15} e^{6 t^{5}} + C

n \to \infty lim ((1)^{n})

\frac{d y}{d x} (x + y) = x - y

\frac{d}{d t} (- e^{2 t})

x \to 0 lim (\frac{cos ( 2 x ) - cos ( 5 x )}{x ^{2}})

\int e^{5 x} cos (3 x) d x

What is the integral of 4t^4e^{6t^5} ?
The integral of 4t^4e^{6t^5} is 2/15 e^{6t^5}+C