What is the sum from n=8 to infinity of cos(1/(n^3)) ?

The sum from n=8 to infinity of cos(1/(n^3)) is diverges

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sum from n=8 to infinity of cos(1/(n^3))

n = 8 \sum \infty cos (\frac{1}{n ^{3}})

diverges

Solution steps

n = 8 \sum \infty cos (\frac{1}{n ^{3}})

Apply Series Divergence Test:

diverges

= diverges

d er i v a t i v e f (x) = sin (3 ln (x))

d er i v a t i v e y = 11 x + 11 x + 11 x

\int x^{2} \cdot cos (x) d x

\int \frac{3 x + 4}{( x ^{2} + 4 ) ( 3 - x )} d x

\frac{d}{d x} (6 cos (4 x))

What is the sum from n=8 to infinity of cos(1/(n^3)) ?
The sum from n=8 to infinity of cos(1/(n^3)) is diverges