We've updated our
Privacy Policy effective December 15.
Please read our updated Privacy Policy and tap
Graph
Hide Plot »
Frequently Asked Questions (FAQ)
What is the solution for y^'=2y+e^{2x}cos(3x),y(0)=4 ?
- The solution for y^'=2y+e^{2x}cos(3x),y(0)=4 is y=(sin(3x))/(3e^{-2x)}+4e^{2x}