(y^2+1)dx=y(sec^2(x))dy

Lösung

(y^{2} + 1) d x = y (sec^{2} (x)) d y

y = e^{x + \frac{1}{2} s i n (2 x) - c_{1}} - 1, y = - e^{x + \frac{1}{2} s i n (2 x) - c_{1}} - 1

Schritte zur Lösung

(y^{2} + 1) d x = y (sec^{2} (x)) d y

Solve separable ODE:

y = e^{x + \frac{1}{2} s i n (2 x) - c_{1}} - 1, y = - e^{x + \frac{1}{2} s i n (2 x) - c_{1}} - 1

y = e^{x + \frac{1}{2} s i n (2 x) - c_{1}} - 1, y = - e^{x + \frac{1}{2} s i n (2 x) - c_{1}} - 1

\frac{\partial}{\partial x} (x - 3 y^{2} + 4 x^{2} y^{3})

y^{^{''}} - 4 y^{^{'}} = 6 t

in v erse l a pl a ce \frac{7 s ^{3} - 9 s + 1}{3 s ^{5}}

\frac{\partial}{\partial z} (cos (x y))

x y y^{^{'}} - y^{2} = x^{4}