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Frequently Asked Questions (FAQ)
What is the solution for y^{''}+4y^'+13y=0,y(0)=7,y^'(0)=7 ?
- The solution for y^{''}+4y^'+13y=0,y(0)=7,y^'(0)=7 is y=e^{-2t}(7cos(3t)+7sin(3t))