What is the derivative of (4x)/(5-tan(x)) ?

The derivative of (4x)/(5-tan(x)) is (4(5-tan(x)+xsec^2(x)))/((5-tan(x))^2)

What is the first derivative of (4x)/(5-tan(x)) ?

The first derivative of (4x)/(5-tan(x)) is (4(5-tan(x)+xsec^2(x)))/((5-tan(x))^2)

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derivative of

\frac{4 x}{5 - tan ( x )}

\frac{4 ( 5 - tan ( x ) + x sec ^{2} ( x ) )}{( 5 - tan ( x ) ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{4 x}{5 - tan ( x )})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (\frac{x}{5 - tan ( x )})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 4 \cdot \frac{\frac{d x}{d x} ( 5 - tan ( x ) ) - \frac{d}{d x} ( 5 - tan ( x ) ) x}{( 5 - tan ( x ) ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (5 - tan (x)) = - sec^{2} (x)

= 4 \cdot \frac{1 \cdot ( 5 - tan ( x ) ) - ( - sec ^{2} ( x ) ) x}{( 5 - tan ( x ) ) ^{2}}

Simplify

4 \cdot \frac{1 \cdot ( 5 - tan ( x ) ) - ( - sec ^{2} ( x ) ) x}{( 5 - tan ( x ) ) ^{2}} : \frac{4 ( 5 - tan ( x ) + x sec ^{2} ( x ) )}{( 5 - tan ( x ) ) ^{2}}

= \frac{4 ( 5 - tan ( x ) + x sec ^{2} ( x ) )}{( 5 - tan ( x ) ) ^{2}}

\int (\frac{1}{x ^{2} + 1}) d x

x d y + y d x = 3 d x

d er i v a t i v e \frac{1 - cos ( x )}{sin ( x )}

y^{^{'}} + \frac{3 x}{x ^{2} + 4} y = \frac{x}{x ^{2} + 4}, y (0) = 1

\int sin^{2} (8 x) d x

What is the derivative of (4x)/(5-tan(x)) ?
The derivative of (4x)/(5-tan(x)) is (4(5-tan(x)+xsec^2(x)))/((5-tan(x))^2)
What is the first derivative of (4x)/(5-tan(x)) ?
The first derivative of (4x)/(5-tan(x)) is (4(5-tan(x)+xsec^2(x)))/((5-tan(x))^2)