What is the integral of (1/(x^2+1)) ?

The integral of (1/(x^2+1)) is arctan(x)+C

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integral of (1/(x^2+1))

\int (\frac{1}{x ^{2} + 1}) d x

arctan (x) + C

Solution steps

\int \frac{1}{x ^{2} + 1} d x

Use the common integral:

\int \frac{1}{x ^{2} + 1} d x = arctan (x)

= arctan (x)

Add a constant to the solution

= arctan (x) + C

x d y + y d x = 3 d x

d er i v a t i v e \frac{1 - cos ( x )}{sin ( x )}

y^{^{'}} + \frac{3 x}{x ^{2} + 4} y = \frac{x}{x ^{2} + 4}, y (0) = 1

\int sin^{2} (8 x) d x

\int e^{- x} d x

What is the integral of (1/(x^2+1)) ?
The integral of (1/(x^2+1)) is arctan(x)+C