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Frequently Asked Questions (FAQ)
What is the solution for x^2y^{''}+3xy^'-24y=0,y(1)=3,y^'(1)=-3 ?
- The solution for x^2y^{''}+3xy^'-24y=0,y(1)=3,y^'(1)=-3 is y=(3-3/2)x^4+3/(2x^6)