We've updated our
Privacy Policy effective December 15.
Please read our updated Privacy Policy and tap
Graph
Hide Plot »
Frequently Asked Questions (FAQ)
What is the solution for 2yy^'+4=y^2+4x ?
- The solution for 2yy^'+4=y^2+4x is y=sqrt(-4x+c_{1)e^x},y=-sqrt(-4x+c_{1)e^x}