What is the sum from n=0 to infinity of 300(-1.41)^n ?

The sum from n=0 to infinity of 300(-1.41)^n is diverges

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sum from n=0 to infinity of 300(-1.41)^n

n = 0 \sum \infty 300 (- 1.41)^{n}

diverges

Solution steps

n = 0 \sum \infty 300 (- 1.41)^{n}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 300 \cdot n = 0 \sum \infty (- 1.41)^{n}

Apply Series Geometric Test:

diverges

= 300 diverges

= diverges

\int \frac{sin ( 20 ) ( x )}{sin ( 10 ) ( x )} d x

d er i v a t i v e 6 cos (3 x + 3)

d er i v a t i v e y = e^{7 x}

l a pl a ce t r an s f or m e^{2 t} cos (2 t)

\frac{d}{d x} (1 - 10 x)

What is the sum from n=0 to infinity of 300(-1.41)^n ?
The sum from n=0 to infinity of 300(-1.41)^n is diverges