What is the derivative of 6cos(3x+3) ?

The derivative of 6cos(3x+3) is -18sin(3x+3)

What is the first derivative of 6cos(3x+3) ?

The first derivative of 6cos(3x+3) is -18sin(3x+3)

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derivative of

6 cos (3 x + 3)

- 18 sin (3 x + 3)

Solution steps

\frac{d}{d x} (6 cos (3 x + 3))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d x} (cos (3 x + 3))

Apply the chain rule:

- sin (3 x + 3) \frac{d}{d x} (3 x + 3)

= - sin (3 x + 3) \frac{d}{d x} (3 x + 3)

\frac{d}{d x} (3 x + 3) = 3

= 6 (- sin (3 x + 3) \cdot 3)

Simplify

= - 18 sin (3 x + 3)

d er i v a t i v e y = e^{7 x}

l a pl a ce t r an s f or m e^{2 t} cos (2 t)

\frac{d}{d x} (1 - 10 x)

y^{^{''}} - 5 y^{^{'}} = (5 t + 9) sin (2 t)

d er i v a t i v e 4 x - 2

What is the derivative of 6cos(3x+3) ?
The derivative of 6cos(3x+3) is -18sin(3x+3)
What is the first derivative of 6cos(3x+3) ?
The first derivative of 6cos(3x+3) is -18sin(3x+3)