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Frequently Asked Questions (FAQ)
What is the solution for y^'=y+e^x,y(0)=(x+c)e^x,y(0)= 1/2 ?
- The solution for y^'=y+e^x,y(0)=(x+c)e^x,y(0)= 1/2 is y=e^xx+c_{1}e^x