y^{''}+0.6y^'+8y=0

Lösung

y^{^{''}} + 0.6 y^{^{'}} + 8 y = 0

y = e^{- \frac{3 t}{10}} (c_{1} cos (\frac{791 t}{10}) + c_{2} sin (\frac{791 t}{10}))

Schritte zur Lösung

y^{''} (t) + 0.6 y^{'} (t) + 8 y = 0

Solve linear ODE:

y = e^{- \frac{3 t}{10}} (c_{1} cos (\frac{791 t}{10}) + c_{2} sin (\frac{791 t}{10}))

y = e^{- \frac{3 t}{10}} (c_{1} cos (\frac{791 t}{10}) + c_{2} sin (\frac{791 t}{10}))

64 y^{^{''}} + 96 y^{^{'}} + 36 y = 0, y (0) = 1, y^{^{'}} (0) = 8

y^{^{''}} + \frac{32}{13} y^{^{'}} + 32 y = 0

0.2 y^{^{''}} + 14 y^{^{'}} + \frac{1}{0.004} y = 0, y (0) = 0

2 \frac{d ^{2} y}{d x ^{2}} + 5 \frac{d y}{d x} + 3 y = 0

y^{^{''}} - 10 y^{^{'}} + 50 y = 0, y (0) = 1, y^{^{'}} (0) = 25