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Beliebt Rechnen >

y^{''}+4y^'+y8=0

Lösung

y^{^{''}} + 4 y^{^{'}} + y 8 = 0

Lösung

y = e^{- 2 t} (c_{1} cos (2 t) + c_{2} sin (2 t))

Schritte zur Lösung

y^{''} (t) + 4 y^{'} (t) + y 8 = 0

Solve linear ODE:

y = e^{- 2 t} (c_{1} cos (2 t) + c_{2} sin (2 t))

y = e^{- 2 t} (c_{1} cos (2 t) + c_{2} sin (2 t))

Graph

Beliebte Beispiele

y^{''}=8y^'-15y,y(0)=0,y^'(0)=-2

y^{^{''}} = 8 y^{^{'}} - 15 y, y (0) = 0, y^{^{'}} (0) = - 2

5y^{''}-3y^'+4y=0

5 y^{^{''}} - 3 y^{^{'}} + 4 y = 0

0.1y^{''}+0.4y^'+2y=0

0.1 y^{^{''}} + 0.4 y^{^{'}} + 2 y = 0

(d^2x)/(dt^2)-x(dx)/(dx)=0

\frac{d ^{2} x}{d t ^{2}} - x \frac{d x}{d x} = 0

y^{'''}+4y^'=0,y(0)=1,y^'(0)=1,y^{''}(0)=1

y^{^{'''}} + 4 y^{^{'}} = 0, y (0) = 1, y^{^{'}} (0) = 1, y^{^{''}} (0) = 1