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Frequently Asked Questions (FAQ)
What is the solution for 144y^{'''}+120y^{''}+25y^'=0 ?
- The solution for 144y^{'''}+120y^{''}+25y^'=0 is y=c_{1}+c_{2}e^{-(5t)/(12)}+c_{3}e^{-(5t)/(12)}t