2y^{'''}-6y^{''}=0

Lösung

2 y^{^{'''}} - 6 y^{^{''}} = 0

y = c_{1} e^{3 t} + c_{2} + c_{3} t

Schritte zur Lösung

2 y^{'''} (t) - 6 y^{''} (t) = 0

Solve linear ODE:

y = c_{1} e^{3 t} + c_{2} + c_{3} t

y = c_{1} e^{3 t} + c_{2} + c_{3} t

y^{^{''}} + 6 y^{^{'}} + 13 y = 0, y (0) = - 3, y^{^{'}} (0) = \frac{1}{3}

2 y^{^{''}} + 3 y^{^{'}} + \frac{2}{5} y = 0

3 y^{^{''}} + 48 y = 0, y (0) = 8, y^{^{'}} (0) = - 33

y^{^{''}} + y^{^{'}} + 2 y = 0, y (0) = y^{^{'}} (0), y^{^{'}} (0) = 0

2 y^{^{''}} + 4 y^{^{'}} - 10 y = 0