2y^{''}+4y^'-10y=0

Lösung

2 y^{^{''}} + 4 y^{^{'}} - 10 y = 0

y = c_{1} e^{(- 1 + 6) t} + c_{2} e^{(- 1 - 6) t}

Schritte zur Lösung

2 y^{''} (t) + 4 y^{'} (t) - 10 y = 0

Solve linear ODE:

y = c_{1} e^{(- 1 + 6) t} + c_{2} e^{(- 1 - 6) t}

y = c_{1} e^{(- 1 + 6) t} + c_{2} e^{(- 1 - 6) t}

y^{^{''''}} - y^{^{'}} = 0

\frac{1}{4} x^{^{''}} - x = 0, x (0) = 1, x^{^{'}} (0) = 5

4 x^{^{''}} + 15 x^{^{'}} + 14 x = 0

y^{^{''}} + 5 y^{^{'}} - 2 y = 0, y (0) = 5, y^{^{'}} (0) = - 5

3 y^{^{''}} + 4 y^{^{'}} + y = 0, y (0) = 2, y^{^{'}} (0) = - 1