y^{''}+6y+34=0,y(0)=1,y^'(0)=7

Lösung

y^{^{''}} + 6 y + 34 = 0, y (0) = 1, y^{^{'}} (0) = 7

y = \frac{20}{3} cos (6 t) + \frac{7}{6} sin (6 t) - \frac{17}{3}

Schritte zur Lösung

y^{''} (t) + 6 y + 34 = 0

Solve linear ODE:

y = \frac{20}{3} cos (6 t) + \frac{7}{6} sin (6 t) - \frac{17}{3}

y = \frac{20}{3} cos (6 t) + \frac{7}{6} sin (6 t) - \frac{17}{3}

y^{^{''}} + 25 y = 2 cos (5.1 t), y (0) = 1, y^{^{'}} (0) = 1

2 y^{^{'}} - 3 = - y + y^{^{''}} + 16 e^{3 x} + 3 e^{2 x} + 5

y^{^{''}} + 2 y^{^{'}} - 3 y = 6 x - 3 e^{2 x}

y^{^{''}} + 3 y^{^{'}} + 2 y = sin (t), y (0) = 1, y^{^{'}} (0) = 1

y^{^{''}} + 4 y + 4 y^{^{''}} = e^{x} x^{2}