de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Rechnen >

y^{''}+25y=2cos(5.1t),y(0)=1,y^'(0)=1

Lösung

y^{^{''}} + 25 y = 2 cos (5.1 t), y (0) = 1, y^{^{'}} (0) = 1

Lösung

y = 2.98019 \dots cos (5 t) + \frac{1}{5} sin (5 t) - 1.98019 \dots cos (5.1 t)

Schritte zur Lösung

y^{''} (t) + 25 y = 2 cos (5.1 t)

Solve linear ODE:

y = 2.98019 \dots cos (5 t) + \frac{1}{5} sin (5 t) - 1.98019 \dots cos (5.1 t)

y = 2.98019 \dots cos (5 t) + \frac{1}{5} sin (5 t) - 1.98019 \dots cos (5.1 t)

Graph

Beliebte Beispiele

2y^'-3=-y+y^{''}+16e^{3x}+3e^{2x}+5

2 y^{^{'}} - 3 = - y + y^{^{''}} + 16 e^{3 x} + 3 e^{2 x} + 5

y^{''}+2y^'-3y=6x-3e^{2x}

y^{^{''}} + 2 y^{^{'}} - 3 y = 6 x - 3 e^{2 x}

y^{''}+3y^'+2y=sin(t),y(0)=1,y^'(0)=1

y^{^{''}} + 3 y^{^{'}} + 2 y = sin (t), y (0) = 1, y^{^{'}} (0) = 1

y^{''}+4y+4y^{''}=e^xx^2

y^{^{''}} + 4 y + 4 y^{^{''}} = e^{x} x^{2}

y^{''}-2y^'-15y=3x

y^{^{''}} - 2 y^{^{'}} - 15 y = 3 x