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Beliebt Rechnen >

y^{''}+4y^'+13y=cos(3x)-sin(3x)

Lösung

y^{^{''}} + 4 y^{^{'}} + 13 y = cos (3 x) - sin (3 x)

Lösung

y = e^{- 2 x} (c_{1} cos (3 x) + c_{2} sin (3 x)) + \frac{1}{20} sin (3 x) + \frac{1}{10} cos (3 x)

Schritte zur Lösung

y^{''} (x) + 4 y^{'} (x) + 13 y = cos (3 x) - sin (3 x)

Solve linear ODE:

y = e^{- 2 x} (c_{1} cos (3 x) + c_{2} sin (3 x)) + \frac{1}{20} sin (3 x) + \frac{1}{10} cos (3 x)

y = e^{- 2 x} (c_{1} cos (3 x) + c_{2} sin (3 x)) + \frac{1}{20} sin (3 x) + \frac{1}{10} cos (3 x)

Graph

Beliebte Beispiele

-x^{''}-3x^'-2=t

- x^{^{''}} - 3 x^{^{'}} - 2 = t

y^{^{''}} - y = - 4 t + 3

x^{''}+x=e^{-2t}sin(t)

x^{^{''}} + x = e^{- 2 t} sin (t)

y^{''}+6y^'+9y=2e^{-2x}+sin(2x)

y^{^{''}} + 6 y^{^{'}} + 9 y = 2 e^{- 2 x} + sin (2 x)

y^{''}+49y=cos(7t),y(0)=-5,y^'(0)=-56

y^{^{''}} + 49 y = cos (7 t), y (0) = - 5, y^{^{'}} (0) = - 56