y^{''}+y^'=10

Lösung

y^{^{''}} + y^{^{'}} = 10

y = c_{1} + c_{2} e^{- t} + 10 t

Schritte zur Lösung

y^{''} (t) + y^{'} (t) = 10

Solve linear ODE:

y = c_{1} + c_{2} e^{- t} + 10 t

y = c_{1} + c_{2} e^{- t} + 10 t

d (x) = 12 x^{2} - 10 x

y^{^{''}} - y^{^{'}} - 6 y = 12 x - e^{x}, y (0) = 1, y^{^{'}} (0) = - 2

y^{^{''}} - 3 y^{^{'}} + 2 y = \frac{e ^{2 x}}{e ^{2 x} + 1}

so l v e f or D, D (t) = 5 cos (\frac{π}{6} t + \frac{7 π}{6}) + 3

y^{^{''}} - 10 y^{^{'}} + 25 y = e^{5 t} ln (t)