y^{''}+5y^'+6y=3

Lösung

y^{^{''}} + 5 y^{^{'}} + 6 y = 3

y = c_{1} e^{- 2 t} + c_{2} e^{- 3 t} + \frac{1}{2}

Schritte zur Lösung

y^{''} (t) + 5 y^{'} (t) + 6 y = 3

Solve linear ODE:

y = c_{1} e^{- 2 t} + c_{2} e^{- 3 t} + \frac{1}{2}

y = c_{1} e^{- 2 t} + c_{2} e^{- 3 t} + \frac{1}{2}

x^{^{''}} + 4 x = cos (t)

y^{^{''}} + 9 y = cos (8 x)

(d^{2} - 2 d + 1) y = x^{2} e^{2} x

y^{^{''}} - y^{^{'}} - 12 y = e^{2 x} + e^{x - 2}

y^{^{''}} - y^{^{'}} = cos (2 x)