y^{''}+25y= 2/3 cos(2)t

Lösung

y^{^{''}} + 25 y = \frac{2}{3} cos (2) t

y = c_{1} cos (5 t) + c_{2} sin (5 t) + \frac{2 cos ( 2 ) t}{75}

Schritte zur Lösung

y^{''} (t) + 25 y = \frac{2}{3} cos (2) t

Solve linear ODE:

y = c_{1} cos (5 t) + c_{2} sin (5 t) + \frac{2 cos ( 2 ) t}{75}

y = c_{1} cos (5 t) + c_{2} sin (5 t) + \frac{2 cos ( 2 ) t}{75}

3 y^{^{''}} + y^{^{'}} = 9 x

x^{^{''}} + 5 x^{^{'}} + 6 x = 2 e^{- t}, x (0) = 1, x^{^{'}} (0) = 0

y^{^{''}} - y = 2 sin (x)

x^{^{''}} - x = 4 e^{t}

y^{^{''}} + y^{^{'}} - 2 y = x^{2} + 3