3y^{''}+y^'=9x

Lösung

3 y^{^{''}} + y^{^{'}} = 9 x

y = c_{1} + c_{2} e^{- \frac{x}{3}} + \frac{9 x ^{2}}{2} - 27 x

Schritte zur Lösung

3 y^{''} (x) + y^{'} (x) = 9 x

Solve linear ODE:

y = c_{1} + c_{2} e^{- \frac{x}{3}} + \frac{9 x ^{2}}{2} - 27 x

y = c_{1} + c_{2} e^{- \frac{x}{3}} + \frac{9 x ^{2}}{2} - 27 x

x^{^{''}} + 5 x^{^{'}} + 6 x = 2 e^{- t}, x (0) = 1, x^{^{'}} (0) = 0

y^{^{''}} - y = 2 sin (x)

x^{^{''}} - x = 4 e^{t}

y^{^{''}} + y^{^{'}} - 2 y = x^{2} + 3

y^{^{'''}} + y^{^{'}} = e^{x}, y (0) = 0