f^'(x)=(x^2)/((f(x))^2),f(1)=2

解答

f^{^{'}} (x) = \frac{x ^{2}}{( f ( x ) ) ^{2}}, f (1) = 2

f (x) = 3 x^{3} + 7

求解步骤

f^{'} (x) = \frac{x ^{2}}{( f ( x ) ) ^{2}}

求解可分离方程:

f (x) = 3 x^{3} + 7

f (x) = 3 x^{3} + 7

y^{^{'}} = 7 x y^{87}

\frac{d p}{d t} = \frac{( p - 900 )}{2}

\frac{d S}{d t} = 0.02 - \frac{S}{490}

x d x + y d y = x y (x d y + y d x)

y^{^{'}} \cdot ln (y) - y = 0