y^'=7xy^{87}

Lösung

y^{^{'}} = 7 x y^{87}

y = 86 - \frac{1}{43 ( 7 x ^{2} + c _{1} )}, y = - 86 - \frac{1}{43 ( 7 x ^{2} + c _{1} )}

Schritte zur Lösung

y^{'} (x) = 7 x y^{87}

Solve separable ODE:

y = 86 - \frac{1}{43 ( 7 x ^{2} + c _{1} )}, y = - 86 - \frac{1}{43 ( 7 x ^{2} + c _{1} )}

y = 86 - \frac{1}{43 ( 7 x ^{2} + c _{1} )}, y = - 86 - \frac{1}{43 ( 7 x ^{2} + c _{1} )}

\frac{d p}{d t} = \frac{( p - 900 )}{2}

\frac{d S}{d t} = 0.02 - \frac{S}{490}

x d x + y d y = x y (x d y + y d x)

y^{^{'}} \cdot ln (y) - y = 0

y^{^{'}} = \frac{( x ^{2} - 5 )}{y ^{2}}, y (0) = 3