xy^2y^'=ln(x)

Lösung

x y^{2} y^{^{'}} = ln (x)

y = 3 \frac{3 ln ^{2} ( x ) + c _{1}}{2}

Schritte zur Lösung

x y^{2} y^{'} (x) = ln (x)

Solve separable ODE:

y = 3 \frac{3 ln ^{2} ( x ) + c _{1}}{2}

y = 3 \frac{3 ln ^{2} ( x ) + c _{1}}{2}

V^{^{'}} - V^{2} = 5

\frac{d y}{d x} = - 5 y

\frac{d y}{d x} = \frac{1 + y ^{2}}{( 1 + x ^{2} ) \cdot x \cdot y}

\frac{d y}{d x} = \frac{y}{5}

\frac{d y}{d t} = 0.07 (100 - y), y (0) = 25