y^'=(ty)/2

Lösung

y^{^{'}} = \frac{t y}{2}

y = e^{\frac{t ^{2}}{4} + c_{1}}

Schritte zur Lösung

y^{'} (t) = \frac{t y}{2}

Solve separable ODE:

y = e^{\frac{t ^{2}}{4} + c_{1}}

y = e^{\frac{t ^{2}}{4} + c_{1}}

\frac{d}{d x} ((f (x)^{- 1}) (11)) = 3 x^{2} - 6 x + 2

y^{^{'}} = x^{2} 2^{y}

10 y^{^{'}} + 5 y = 0

(3 x^{2} + 2)^{3} y^{^{'}} - x y^{2} = 0, y (0) = 2

\frac{d y}{d x} y = 8 x arcsin (x)