What is the solution for 3+2q+(4+2p)(dq)/(dp)=0 ?

The solution for 3+2q+(4+2p)(dq)/(dp)=0 is q=(c_{1})/(2(4+2p))-3/2

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3+2q+(4+2p)(dq)/(dp)=0

3 + 2 q + (4 + 2 p) \frac{d q}{d p} = 0

q = \frac{c _{1}}{2 ( 4 + 2 p )} - \frac{3}{2}

Solution steps

3 + 2 q + (4 + 2 p) \frac{d q}{d p} = 0

Solve separable ODE:

q = \frac{c _{1}}{2 ( 4 + 2 p )} - \frac{3}{2}

q = \frac{c _{1}}{2 ( 4 + 2 p )} - \frac{3}{2}

What is the solution for 3+2q+(4+2p)(dq)/(dp)=0 ?
The solution for 3+2q+(4+2p)(dq)/(dp)=0 is q=(c_{1})/(2(4+2p))-3/2